
Q: 8. S. aureus on Mannitol Salt Agar appears as yellow colonies on yellow agar. Why?
(a) S. aureus produces yellow pigment (b) S. aureus ferments mannitol, producing acid that changes phenol red to
yellow (c) The salt concentration causes colour change (d) S. aureus produces urease
A: (b) S. aureus ferments mannitol → acid production → pH drops from 8.4 to 6.8 → phenol red indicator changes
from red to yellow. This is the DIFFERENTIAL function of MSA.
EXTENDED SHORT ANSWER PRACTICE
These mirror the 3 extended short answer questions in your exam. Practice writing concise but complete answers.
Q: Extended Q1: You are given an unknown Gram-negative rod isolated from a patient's urine sample.
Describe a systematic approach to identify this organism, including at least 4 specific tests and the
expected results for E. coli.
A: Step 1: Confirm Gram stain result — Gram-negative rod. Step 2: Oxidase test — E. coli is oxidase NEGATIVE
(confirms Enterobacteriaceae). If positive, consider Pseudomonas. Step 3: MacConkey agar — E. coli is a lactose
fermenter → PINK colonies on MAC. Step 4: IMViC tests — E. coli pattern is I+ M+ V− C− (Indole positive, Methyl
Red positive, VP negative, Citrate negative). Step 5: Motility test — E. coli is MOTILE (distinguishes from non-motile
Klebsiella which shares some IMViC results). Additional: ONPG test would be positive (has beta-galactosidase),
confirming lactose fermentation ability.
Q: Extended Q2: Explain why Mycoplasma cannot be identified using Gram staining. Describe 3 unique
characteristics of Mycoplasma and explain why antibiotics like penicillin would be ineffective.
A: Mycoplasma LACKS A CELL WALL entirely. The Gram stain works by differentiating bacteria based on cell wall
structure — Gram-positive bacteria retain crystal violet due to thick peptidoglycan, while Gram-negative cells lose it
through their thin peptidoglycan layer. Without any cell wall, Mycoplasma cannot retain or lose the crystal violet in a
meaningful way, making Gram staining useless. 3 Unique characteristics: (1) PLEOMORPHIC shape — without a
rigid cell wall, the cell membrane alone determines shape, which varies constantly. (2) FRIED EGG colony
appearance — distinctive morphology with dense centre and thin periphery, colonies are tiny (0.1–0.25 µm). (3)
Requires STEROLS in growth media — Mycoplasma cannot synthesize sterols, which other bacteria don't need
because their cell wall provides structural support. Penicillin is ineffective because it works by inhibiting
peptidoglycan synthesis (specifically, it blocks transpeptidase enzymes that cross-link peptidoglycan chains). Since
Mycoplasma has NO peptidoglycan (no cell wall at all), penicillin has no target.
Q: Extended Q3: Compare and contrast the Methyl Red and Voges-Proskauer tests. Include: what they
test for, what medium is used, what reagents are added, and how to interpret the results. Give an
example organism for each positive result.
A: Both tests use the same medium: MRVP broth (contains peptone, glucose, and buffer). Both test how bacteria
ferment glucose, but they detect DIFFERENT end products from two alternative pathways. METHYL RED TEST:
Tests for mixed acid fermentation products (lactate, acetate, formate). After incubation, the pH indicator methyl red
is added. If stable acid end products are present, they overcome the buffer and maintain an acidic pH → methyl red
stays RED = POSITIVE. Example: E. coli (MR+). If the organism produces neutral products instead (butanediol), the
acids are consumed and the medium becomes less acidic → methyl red turns YELLOW = NEGATIVE.
VOGES-PROSKAUER TEST: Tests for the butanediol pathway, specifically for the intermediate acetoin (acetyl
methyl carbinol). After incubation, alpha-naphthol and KOH (Barritt's reagents) are added. If acetoin is present, it
reacts with these reagents to produce a RED/dark pink colour = POSITIVE. Example: Enterobacter aerogenes
(VP+). If no acetoin is present, no colour change = NEGATIVE. The key relationship: these pathways are generally
mutually exclusive. An organism that is MR+ is typically VP− (E. coli: MR+ VP−), and vice versa (Enterobacter: MR−
VP+). This makes the MR/VP pair a powerful differential tool.
Microbiology — Ultimate Study Guide | Page 26 of 27